A calorimeter of thermal capacity 80j contains 20g of water at 25°C. Water at 100°C is added so…

JAMB 1980

A calorimeter of thermal capacity 80j contains 20g of water at 25°C. Water at 100°C is added so that the final temperature of the set-ups is 50°C. The amount of water added is (Heat capacity of water = 4.18J/g/°C)

A. 20g

B. 25g

C. 45g

D. 50g

E. 100g

Correct Answer: Option A

Explanation

Heat lost = heat gained

mcθ = cθ + mcθ

m x 4.18 x (100 – 50) = 80(50 -25) + [20 x 4.18] x (50 – 25)

Do the math;

m = 20g

Explain your answer in the comment box below and let’s have a discussion so as to have a great understanding of this question!

PREVIOUS           NEXT

GO BACK TO THE PAST QUESTIONS PAGE

If you find this post beneficial, feel free to use the share button to share with friends.

Follow us on our Facebook page and subscribe to this website for more updates by hitting on the bell icon by the bottom left corner of your screen!